Math, asked by jiteshturuk, 1 month ago

The sum of a natural number and its reseprocal is 65/8. find the natural number.​

Answers

Answered by amitsharma777222999
1

Step-by-step explanation:

x+1/x=65/8

8x^2-65x+8=0

8x^2-64x-x+8=0

8x(x-8)-1(x-8)=0

(8x-1)(x-8)=0

x=8

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