Question

the sum of a natural number and its square is 42 find the numbers​

Answer 1

Let the number be X

x + x² = 42

x² + x - 42 = 0

x² + 6x - 7x - 42 = 0

x ( x + 6 ) - 7 ( x + 6 ) = 0

( x + 6 ) ( x - 7 ) = 0

x = - 6 , 7

So , the numbers are - 6 and 7 .