the sum of a number and it's reciprocal is 10/3 find the sum
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Let the number be x
:. According to given statement
x+1x=103
⇒x2+1x=103
⇒3x2+3=10x
⇒3x2−10x+3=0
⇒3x2−(9+1)x+3=0
⇒3x2−9x−x+3=0
⇒3x(x−3)−1(x−3)=0
⇒(3x−1)(x−3)=0
when 3x−1=0, x=13
and when x-3=0, x=3
Hence, the number (s) are 3 and (1)/(3)
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