find two numbers whose sum is 28 and product is 192
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suppose two natural number is x and y
x+y=28
x=28−y
product of the number
x×y=192
put the value of x
(28−y)×y=192
28y−y
2
−192=0
y
2
−28y+192=0
y(y−16)−12(y−16)=0
(y−16)(y−12)
y=12
or
y=16
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