Question

2. A positive number is 5 times another number. If 21 is added to both the numbers.
then one of the new numbers becomes twice the other new number. What are the
numbers?
ahorir o When we interchange the digits, it is
Sum of​

Answer 1

Answer:

Answer:

Correct Question :-

A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers.

Given :-

A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the another new number.

To Find :-

What are the numbers.

Solution :-

Let, the another number be x

And, the positive number will be 5x

Now, 21 added to both the number then,

$\mapsto$ New other number = x + 21

$\mapsto$ New positive number = 5x + 21

According to the question,

$\implies \sf 5x + 21 =\: 2(x + 21)$

$\implies \sf 5x + 21 =\: 2x + 42$

$\implies \sf 5x - 2x =\: 42 - 21$

$\implies \sf 3x =\: 21$

$\implies \sf x =\: \dfrac{\cancel{21}}{\cancel{3}}$

$\implies \sf\bold{\pink{x =\: 7}}$

Hence, the required numbers are :

➲ Another number :

↦ $\sf x$

➦ $\sf\bold{\red{7}}$

And,

➲ Positive number :

↦ $\sf 5x$

↦ $\sf 5(7)$

↦ $\sf 5 \times 7$

➦ $\sf\bold{\red{35}}$

$\therefore$ The numbers are 7 and 35.

Answer 2

Answer:

Linear Equations in One Variable

A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers? Thus, the required numbers are 7 and 35.