The sum of a number and it's reciprocal is 61/30. Find the number?
praveen09:
sme 1 ans ..urgent
Answers
Answered by
8
Let no. be x
As per question,
x+(1/x) = 61/30
=> 30(x²+1) = 61x
=> 30x²+30-61x = 0
On solving this quadratic equation using Sridharacharya's method, we get,
x = 1.2 or 0.833
As per question,
x+(1/x) = 61/30
=> 30(x²+1) = 61x
=> 30x²+30-61x = 0
On solving this quadratic equation using Sridharacharya's method, we get,
x = 1.2 or 0.833
wht s sridharacharyas method
It's really painful to type... It would be better if you looked it up
Answered by
0
Answer:
Step-by-step explanation:
Let a be the number, then by the question a+(1/a)=61/30
30*(a^2)-61a+30=0
30(a^2)-36a-25a+30=0
(6a-5)(5a-6)=0
a=5/6,6/5
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