Question

The sum of a number and it's square is 132, find the number ?​

Answer 1

Answer:

The number is 121, because 121 +121^0.5 = 121 + 11 = 132.

Let the number be x. Then x +x^0.5 = 132, or

Let x = y^2, so we have

y^2+y-132=0

(y-11)(y+12)=0, or

y = 11 or -12, or

x - 121 or 144 (ruled out)

So x = 121.