Question

the sum of a number and its one third is36. find the number

Answer 1

$\mathsf{\text {Let the number be x} }$

$\mathsf{\text{One third of the number = } \dfrac{1}{3}x }$

$\mathsf{\text {Sum of the two numbers is 36.} }$

$\mathsf{\text {Form equation:} }$

$\mathsf{\text {The sum of the number and its one third is 36.}}$

$\mathsf{x + \dfrac{1}{3}x = 36}$

$\mathsf{\dfrac{4}{3}x = 36}$

$\mathsf{x = 36 \div \dfrac{4}{3}}$

$\mathsf{x = 36 \times \dfrac{3}{4}}$

$\mathsf{x = \dfrac{36 \times 3}{4}}$

$\mathsf{x = \dfrac{108}{4}}$

$\mathsf{x = 27}$

$\mathsf{\textbf{Answer: The number is 27.}}$

Answer 2

let the number be x
then according to question
x+x/3=36
x+x/3=36
3x+x=108
4x=108
x=108/4=27 answer

hence your number is 27