The sum of a number and its reciprocal is 10/3 find the number
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7
Let x = the number
Then, x + 1/x = 10/3
Multiply through by the LCD, 3x, to get 3x2 + 3 = 10x
3x2 - 10x + 3 = 0
(3x - 1)(x - 3) = 0
So, x = 1/3 or x = 3
Then, x + 1/x = 10/3
Multiply through by the LCD, 3x, to get 3x2 + 3 = 10x
3x2 - 10x + 3 = 0
(3x - 1)(x - 3) = 0
So, x = 1/3 or x = 3
logesh25:
=10/3
Answered by
2
x+1/x=10/3
x^2+1/x=10/3
3x^2+3=10x
3x^2-10x+3=0
(x-3) (3x-1) =0
x=3 (or) x=1/3
x^2+1/x=10/3
3x^2+3=10x
3x^2-10x+3=0
(x-3) (3x-1) =0
x=3 (or) x=1/3
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