Question

The sum of a number and its reciprocal is 10 by 3 find the numbers

Answer 1

Let x be the no. Then x+1/x=10/3 =>3x^2+3=10x=>3x^2-10x+3=0 so by using middle term factor 3x^2-9x-x+3=0 =>3x(x-3)-1(x-3)=0 =>(x-3)(3x-1)=0 hence x has 2 values that is 3 and 1/3 plz plz plz like the answer

Answer 2

Answer:

let the no. be x

given x+1/x=10/3

therefore, x^2+1/x=10/3

x^2+1=10x/3

3(x^2+1)=10x

3x^2+3-10x=0

3x^2-10X+3=0

3x^2-9x-x+3=0[3(3)=9 ;-9(-1)=9 ;-9-1=-10]

3x(x-3)-1(x-3)=0

(x-3)(3x-1)=0

therefore,x-3=0

                x=3

(or)3x-1=0

 x=1/3

therefore the no. is 3 because 1/3 is a fraction