Question

the sum of a number and its
reciprocal is one-eight of 34 then find the proudct of the number and its squareroot


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Answer 1

let the no. be x

its reciprocal be 1/x

A.T.Q.

x+1/x=34/8

$x {}^{2} + 1 \times \frac{1}{x} = \frac{34}{8}$

x square +1 =34x/8

x sq. =34x/8 -1

xsq. = 34x-8/8

x sq.=2(17x-4)/8

x sq.=17x-4

xsq. -17x +4=0

ans