Question

The sum of a number and the number preceding it is 33. by how much is two less than six times thenumber?

Answer 1

so the no is 33+1 =34
$34(6) - 2 \\ 204 - 2 \\ 202 \\ \\ \\ so \: the \: no \: is \: 202$
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Answer 2

Answer:

The answer is 94.

Step-by-step explanation:

Step 1:

Let us assume the number be n,

They mentioned preceding number= n+1

Sum of both the number is 33.

i,e; Sum= n+n+1=33.

Step 2:

Simplify the sum:

Adding n we get 2n

i.e.; 2n+1=33

Step3:

We need to find the value of n, so move 1 to RHS by doing the sign will be changed.

2n=33-1

Step 3:

Subtract RHS

2n=32

Product value of n move to RHS, so it will be moved in Denominator of RHS.

n=32/2

Divide 32 by 2.

n=16.

We got the n value as 16

Step 4:

They ask us to find, how much is 2 < 6n

We know the ‘n’ value by using this we will find 6 times of number

i.e.; 6 x 16=96

Subtract =96-2=94

Finally we got the number 94.