Question

The sum of a number of 2 digit and of the number formed by reversing the digits is 110. and the difference of tge digit is 6 . find the number.

Answer 1

let the 1st and the larger no be x

2nd and smaller no be y

according to the question,

10x + y + 10y + x = 110

11x + 11y = 110

11(x+y)= 110

x+y = 110/11

x+y = 10 ----------- 1

its given that ,

x-y = 6 -------------2

now we can solve the eq's using elimination method ,

x+y=10

-(x-y=6)

--------------

2y=4

y= 4/2

y = 2

now we can substitute the value of y in eq 1

x+y=10

x+2=10

x=10-2

x=8

hence the no is 82

hope this ans is helpful :)