The sum of two numbers is 520. if the bigger number is decreased by 4% and the smaller number incresed by 12%, then the numbers obtained are equal. the smaller number is
Answers
Answered by
1
Let the bigger number is a and the smaller number is (520 - a)
According to the question,
a×(100−4)100=(520−a)×(100+12100)a×(100−4)100=(520−a)×(100+12100)
96a100=(520−a)11210096a100=(520−a)112100
96a=(520−a)11296a=(520−a)112
13a=364013a=3640
a=280
According to the question,
a×(100−4)100=(520−a)×(100+12100)a×(100−4)100=(520−a)×(100+12100)
96a100=(520−a)11210096a100=(520−a)112100
96a=(520−a)11296a=(520−a)112
13a=364013a=3640
a=280
Answered by
0
Let the bigger number be x
The smaller number is (520 - x)
The bigger number is decreased by 4%:
4% of the number = 0.04x
Number after decreased = x - 0.04x = 0.96x
The smaller number is increased by 12%:
increased = 0.12( 520 - x) = 62.4 - 0.12x
Number after increased = (520 - x) + (62.4 - 0.12x) = 582.4 - 1.12x
Solve x:
Given that the two numbers obtained are equal
582.4 - 1.12x = 0.96x
1.12x + 0.96x = 582.4
2.06x = 582.4
x = 280
Find the numbers:
The bigger number = x = 280
The smaller number = 520 - x = 520 - 280 = 240
Answer: The smaller number is 240
Similar questions