The sum of a number of 2 digits and of the number formed by reversing the digits is 110 , and the difference of the digits is 6 find the number
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if the two digit number is 10x+y
and reverse be 10y+x
Step-by-step explanation:
according to question
x-y=6
so x=6+y......(1)
(10x+y)+(10y+x)=110....(2)
put eq1in2
we get
{10(y+6)+y}+{10y+y+6}=110
10y+60+y+11y+6=110
11y+11y+60+6=110
22y+66=110
22y=110-66
22y=44
y=2
x=2+6=8
the number is 10x+y-10(8)+2=82
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