The sum of a number of 2 digits and of the number formed by reversing the digits is 110 , and the difference of the digits is 6. Find the number.
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Answered by
1
Answer:
Answer = 82,28
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Answered by
1
Step-by-step explanation:
Let the digit in units place be x
and the digit in tens place be y
Then the number=10y+x
number formed by reversing=10x+y
by problem,
(10y+x)+(10x+y)=110
11x+11y=110
divide the equation by 11,then we get
x +y=10...….......(1)
x-y=6...............(2)
by solving the equation ,we get
2x=16(+y and -y get canaled)
x=16/2
x=8
substitute x value in equation (1)
8+y =10
y=10-8
y=2
substitute x,y value in (10y+x) and (10x+y),then we get
10×2+8
=20+8
=28
and
10×8+2
=80+2
=82
the numbers are 28 and 82
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