The sum of a number of 2 digits and of the number formed by reversing the digits is 110 and the difference of the digits is 6. Find the number.
Answers
digit at one's place= x:: digit at tens place=y number= 10y+x:::: reversed number=》10x+y:::: 1st condition=10y+x+10x+y=110;;;; or 11x+11y=110:::: or x+y=10 ;;;;;
2nd condition= x_y=6 comparing 1st &2nd:;;; ;we get x=8 & y= 2 :, required number=28
hope it works ✌️
Answer:
82
Step-by-step explanation:
Let the number at tens place and at units place of two digit number be x and y respectively.
hence, the original number will be (10x+y).
if the digits are reversed then the number will become (10y+x).
According to the 1st condn,
(10x+y) + (10y+x) = 110
10x + y + 10y + x = 110
11x + 11y = 110
Dividing throughout by 11, we get,
x + y = 10..............1
According to the 2nd condn,
x - y = 6................2
Adding eqn 1 & 2, we get,
x + y = 10
+ x - y = 6
therefore, 2x=16
x=8
substituting x=8 in eqn 2,
8 - y = 6
y = 2
the required no. is 82.