Question

the sum of a number of two digits and of the number formed by reversing the digits is 110 and the difference of the digits is 6 find the number​

Answer 1

Step-by-step explanation:

The number obtained by reversing the digits of 64 is 46. Thus, the sum of the number and the number formed by interchanging the digits is 110. The sum of the digits of the number 64 is 10. Thus, if 10 is subtracted from the number 54, the result is equal to 4 more than 5 times the sum of the digits.

Answer 2

Answer:

HOPE YOU UNDERSTAND!

Step-by-step explanation:

let the digits in unit place be x and in ten's place by y .

:. the number = 10y+x

Given, 10y+x+10x+y=110

or, 11(x+y)=10________(1)

or, x+y=6__________(2)

Solving (1) and (2)

2x=16 => x=8

putting the value of x in (1)

8+y=10 =>y=2

:. the number is =2*10+8

=28