Question

The sum of a pairs of opposite angles of a parallelogram is 140°. find the measure of each of its angle.​

Answer 1

Step-by-step explanation:

see the attachment

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Answer 2

Answer:-

ABCD is a parallelogram.

$\sf \: ∠B+∠D=140°$

∠B=∠D (opposite angles of a parallelogram are equal)

$\sf \: ∠B=∠B=140°$

$\sf \longrightarrow \: 2∠B=140°$

$\sf \longrightarrow \: ∠B= \frac{ 140°}{2}$

$\sf \longrightarrow \: ∠B=70°$

Now ∠B+∠C=180°

(adjacent angles of a parallelogram are supplementary )

$\sf \: ∠C=180° −∠B=180° −70°$

$\sf \longrightarrow \: ∠C=110°$

$\sf \: ∴∠A=∠C=110°$

(opp. angles of parallelogram are equal)

$\sf \: ∴∠B=∠D=70°$

$\sf \: and \: ∠A=∠C=110°$

$\sf$