The sum of a two digit number and number obtained on reversing the digit is 99. If number obtained on reversing the digits is 9 more than the original number, find the number
Answers
Answered by
3
let the 2 no be
tens place=x
ones place=y
therefore the no is 10x+y
reversed no=10y+x
according to question
x-y=3 .........eq1
given (10x+y)+(10y+x)=99
11x+11y=99
x+y=9........eq2
eq1-eq2
tens place=x
ones place=y
therefore the no is 10x+y
reversed no=10y+x
according to question
x-y=3 .........eq1
given (10x+y)+(10y+x)=99
11x+11y=99
x+y=9........eq2
eq1-eq2
Similar questions