The sum of a two digit number and the number formed by reversing its digit is 77. What are the possible number satisfying this condition?
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the numbers are 43 and 34,other combinations are 25 and 52,61 and 16
take the digits as x and y.
then original number will be 10y+x
and reversing this number will give you 10x+y
therefore,(10y+x) +(10x+y) =77
solve this equation
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