The sum of a two digit number and the number formed by inter changing its digits is 110. If 20 is subtracted from the original number, the new number is 4 more than 4 times the sum of the digits in the original number. Find the original number.
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let two digut no is xy
original =10x+y
interchanging=10y+x
sum=10x+y+10y+x=11x+11y=110
x+y=10......(1)
(10x+y)-20=4(x+y)+4
6x-3y=24
2x-y=8.....(2)
by (1)(2)
x=6,y=4
number is 64
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