Question

The sum of a two digit number and the number obtained by reversing the order of the digits is 99. Find the number, if the digits different by 3.

Answer 1

Answer:let the digits are x and y so..

If i write a no. xy then= 10x + y

e.g. 32= 10×3+2

so.. reversing of xy is yx and

yx=10y+x

Now..

A/Q : x-y=3 eq1

10x+ y+ 10y+x = 99 eq 2

so from eq 2

10x+y+10y+x= 99

11x+11y=99

x+y=9 ...... eq 3

Now

from eq 1

we have

x-y=3

x=3+y

substituing value of x in eq 3

x+y=9

3+y+y=9

2y=6

y=3

Substituting value of y in eq1

x-y=3

x-3=3

x=6

so the no. is 36 or 63

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