The sum of a two digit number and the number obtained by reversing the order of the digits is 99. Find the number, if the digits different by 3.
Answers
Answered by
0
Answer:let the digits are x and y so..
If i write a no. xy then= 10x + y
e.g. 32= 10×3+2
so.. reversing of xy is yx and
yx=10y+x
Now..
A/Q : x-y=3 eq1
10x+ y+ 10y+x = 99 eq 2
so from eq 2
10x+y+10y+x= 99
11x+11y=99
x+y=9 ...... eq 3
Now
from eq 1
we have
x-y=3
x=3+y
substituing value of x in eq 3
x+y=9
3+y+y=9
2y=6
y=3
Substituting value of y in eq1
x-y=3
x-3=3
x=6
so the no. is 36 or 63
plz mark me as a brainliest
Similar questions
Social Sciences,
5 months ago
Math,
5 months ago
Accountancy,
5 months ago
History,
10 months ago
Social Sciences,
10 months ago