The sum of a two-digit number and the number obtained by reversing the order of digits is 99.
Find the number if the digits differ by 3
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Asked on November 22, 2019 by
Bhavani Praveen
The sum of a two digit number and the number obtained by reversing the order of its digits is 99. If the digits differ by 3, find the number.
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ANSWER
Let the 2 digits be x,y. respectively
2 digit number =10x+y
2 digit number obtained by ususing the digit =10y+x
∴10x+y+10y+x=99
⇒11x+11y=99
⇒x+y=9
x−y=3
On adding : 2x=12
x=6
putting x in ⟶(i)
6+y=9
y=3
∴ Number =10x+y=63
or , 10y+x=36.
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