The sum of a two digit number and the number obtained by reversing its digit is 121 find the number if its unit place digit is 5
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Answer:
Let the digits be x and y
Then number is 10x+y
The number after reversing the digits 10y+x
10x+y + 10y+x =121
11x+11y=121
x+y=11
Since units place digit is 5, 10th place digit = 6
The number is 6×10+5=65 Ans
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