Question

the sum of a two digit number and the number obtained by reversing the order of its digit is 165 if the digit difference by 3 find the number

Answer 1

Let the units digit be y and ten's digit be x
So original no. =10 x+y

Reversing the digits,
New no. = 10y +x

Now,
10x+y+10y+x=165
11 x +11 y =165
x+ y=15
x=15-y _(1)

According to the question,
X-y = 3 _(2)

Substituting (1)in (2),
15-y-y =3
-2y =3-15 = - 12
y=6

So,
X = 15-6=9

The no. is 96

Hope it helps you dear ☺️☺️

Answer 2

Let the ones place digit be x and the tens place digit be y.
Therefore , the number will be 10x + y
After reversing the order of digits, the number will be 10y + x
ATQ,
10x + y + 10y + x = 165
11x + 11y = 165
11 ( x + y ) = 165
x + y = 15 .................(1)

Also,
x - y = 3...................(2)

Add equation (1) and (2), we get
2x = 18
x = 9
put this in equation (1)
9 + y = 15
y = 6

the number is 10x + y = 10 × 9 + 6 = 90 + 6 = 96
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