Question

The sum of a two-digit number and the number obtained by reversing the order of its digit is 99. if the digits differ by 3, find the number.

Answer 1

Let the once digit = x. YLet the tense digit = y
(10y + x)(10x + y) = 99. -----------------(1)
Y - x =3. ------------------(2)
Then u can simply sove these equation

Answer 2

10x+y +10y+x= 99
11x+11y= 99
x-y= 3(given)
so, x+y= 9
x-y=3
so,2x= 12
x = 6
y= 3 ans.