Question

the sum of a two digit number and the number obtained by interchanging the digits of the number is 121 if the digits of the number differ by 3 find the number find the number

Answer 1

here you go ☆☆

▪let no. at ones place = x
▪and no. at tenth place = y
▪so no. is 10y + x
▪no. obtained by inter changing = 10x + y

▪10y + x + 10x + y = 121
▪11y + 11x = 121
▪11 (x+y) = 121

□x + y = 11_________1

□x - y = 3 ___________2

◇adding 1 and 2

x + y = 11
x - y = 3
________
2x = 8

X = 8/2 =>4

▪X = 4

◇from 2

4 -y = 3
-y = 3-4 =>-1

▪y = 1

so no. is 41

hope it helps:)

Answer 2

let the two numbers be xand x+3

x+(x+3)=7
2x+3=7
2x=7-3
2x=4
x=4/2
x=2

x+3=2+3=5
the number=25 or52
instead of 121 I took the number 7
I took other example because I want you to try it by yourself....
this will improve your thinking skill about Maths..
please mark as brainliest.