Question

the sum of a two digit number and the number obtained by reversing the digit is 66 if the digit of the number which differ by 2 find the number how many such numbers are there

Answer 1

Answer:

The number is 42

Step-by-step explanation:

Let the number be: (10*y)+x       (Since, 82=10*8+2)

And the bigger digit be y

If the digits  are reversed, the new number is (10*x)+y

Now, 10y+x+10x+y=66

y+x=6

and y-x=2

So, y=4

and x=2

Hence, the number is 42.

Hope, this helps :)