the sum of a two digit number and the number obtained by reversing the order of its digit is 165 .if the digits differ by 3, find the numbers??
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Answer:
96 (or) 69
Step-by-step explanation:
Let the digit at units place be x and the digit at tens place be y.
Then the number be 10y + x.
Number obtained by reversing the digits is 10x + y.
According to the given condition, we get
(10x + y)(10y + x) = 165
x + y = 15 ---- (1)
It is given that difference of the digits is 3.
x - y = ±3.
Now,
(1)
x + y = 15
x - y = 3
---------------
2x = 18
x = 9.
Substitute x = 9 in (1), we get
x + y = 15
9 + y = 15
y = 6.
Hence, the number is 96.
(ii)
x + y = 15
x - y = -3
---------------
2x = 12
x = 6.
Substitute x = 6, we get
x + y = 15
6 + y = 15
y = 9
Hence, the number is 69.
Therefore, the numbers are 96 (or) 69.
Hope it helps!
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