The sum of a two digit number is 11 .if the number obtained by reversing the digits is 9 less than the original number ,find the number
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Step-by-step explanation:
let the no. at ten's place be x
sum of numbers 11
no. at ones place 11-x
no. =10*tens +ones.
10x+11-x
9x+11
After INTERCHANGING the numbers
the no. at ten's place 11-x
no. at ones place x
no. =10*tens +ones.
( 11-x) 10+x
110-10x+x
=110-9x
the number obtained by reversing the digits is 9 less than the original number
ATQ. 110-9X+9=9X+11
110+9-11=9X+9X
108=18X
X=108/18
x=6
9x+11=9*6+11
=65
SO THE NUMBER IS 65
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