the sum of a two digit number is 12. If 18 is added to it, the digits ate reversed. Find the number.
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Answered by
17
here is your answer mate.....
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nishka5:
how did u get 10n in the second equation?????
Answered by
14
let the tens place digit be x and units place digit be y
original no. = 10x+y
reversed no.= 10y+x
a/q from 1st part--
x+y=12. ---(i)
a/q from 2nd part
10x+y+18=10y+x
9x-9y= -18
x-y= -2. -----(ii)
adding eq i and ii
2x=10
x=5
putting x=5 in eq i
5+y=12
y= 7
original no. = 10x+y
reversed no.= 10y+x
a/q from 1st part--
x+y=12. ---(i)
a/q from 2nd part
10x+y+18=10y+x
9x-9y= -18
x-y= -2. -----(ii)
adding eq i and ii
2x=10
x=5
putting x=5 in eq i
5+y=12
y= 7
hmm.... I have done it
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10
std
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