Question

the sum of a two digit number is 12 if the new number formed by reversing the digit is great is greater than the original number by 54 find the original number

Answer 1

let the unit digit be X
then ten digit = 12-x
the original no. = 10(12-x)+(X)=120-10x+X
=120-9x
the reverse digit =10(X)+(12-x)*=9x+12
According to question
9x+12+54=120-9x
9x+66=120-9x
18x=54
X=3
replacing x in 10(12-x)+(X)
=120-30+3
=93

Answer 2

hope this will help you