Question

The sum of a two digit number is 15. The number obtained by reversing the order of digits of the given number exceeds the given number by 9.Find the given number.
solve this question ...please...​

Answer 1

ANNYEONG :)
__________________

Given that both digits of the number sums 15.

So,

Let the tens digit be 15 - x
And once digit be x

[We know that any two digit number can also be written in the form of (a×10+b)]

Now,

Original number :

=(x × 10) + (15 - x)
=10x + 15 - x
=10x - x + 15

=9x + 15 ( equation 1.)

Number after reversing :

=(15 - x)10+ x
=150 - 10x + x

= 150 - 9x ( equation 2)

Now,
According to question :

$(9x + 15) + 9 = 150 - 9x \\ \\ 9x + 24 = 150 - 9x \\ \\ 9x + 9x = 150 - 24 \\ \\ 18x = 126 \\ \\ x = \frac{126}{18} \\ \\ x = 7$


So,
The unit digit is 7 (x)

And the tens digit :

= 15 - x
= 15 - 7

==> 8

So, the number = 78

${\underline {\underline {VERIFY :--}}}$

= 78 + 9

= 87

Answer 2

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