the sum of a two digit number is 4 more than 5 times the sum of the digit . find the number
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Answer:
Step-by-step explanation:
Let the ones digit be x and tens digit be y
Required number is 10 * x + y
According to the question
(10 * x + y )+ ( 10 * y + x) = 5 * (x + y) + 4
On adding
11 * x + 11 * y = 5 *x + 5 * y + 4
6 *x + 6 * y = 4
(x + y) = 4/6
(x + y) = 2/3
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