The sum of a two digit number is 9. If 27 is added to the number , the digits are reversed. Find the number.
Answers
Answered by
809
let the number be xy
x+y=9...............(1)
(10x+y)+27=10y+x
10x-x+y-10y=-27
9x-9y=-27
x-y=-3................(2)
add equation 1 and 2
we get
x=3
substitute it in eq 1
y=6
so the number is 36
x+y=9...............(1)
(10x+y)+27=10y+x
10x-x+y-10y=-27
9x-9y=-27
x-y=-3................(2)
add equation 1 and 2
we get
x=3
substitute it in eq 1
y=6
so the number is 36
Answered by
104
Answer:
Let the digit at unit's place be y and the digit at ten's place be x.
So, the number will be 10x+y
According to the first condition-
⇒x+y=9 ....(1)
According to the second condition-
⇒10y+x=10x+y+27⇒9y=9x+27
⇒y=x+3 ...(2)
Put the value of y in (2), we have
⇒x+x+3=9
⇒x=3
⇒x+y=9
⇒3+y=9
⇒y=6
∴ the number is 36
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