Question

The sum of a two digit numbers is 12.If the new number formed by reversing the digits is greater than the original number by 18, find the number...... ................... ....plz solve with full steps .........plz don't spam

Answer 1

$\large\bf\underline {To \: find:-}$

• we need to find the original number.

$\huge\bf\underline{Solution:-}$

$\bf\underline{\red{Given:-}}$

• Sum of digits of a two digit number is 12

• the new number formed by reversing the digits is greater than the original number by 18.

${ \blue{ \mathscr{ \underline{Let : - }}}}$

• Let units place digit be x
• Let ten's place digit be y
• Number = 10x + y

$\underline{ \large \red{ \mathscr{A \bf{ccourding} \: to \: \mathscr {Q} \bf{uestion} ....}}}$

⚘ Sum of digits of a two digit number is 12

• x + y = 12
• x = 12 - y .....1)

the new number formed by reversing the digits is greater than the original number by 18

• Reversed number = 10y + x

⇝ 10y + x = 10x + y + 18

⇝ 9y - 9x = 18

• Dividing both sides by 9

⇝ y - x = 2

• From 1)

⇝ y - (12 - y) = 2

⇝ y - 12 + y = 2

⇝ 2y = 14

⇝ y = 14/2

⇝ y = 7

• putting value of y in 1)

⇝ x = 12 - y

⇝ x = 12 - 7

⇝ x = 5

So,

• Original number is 10x + y = 57

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Answer 2

Answer:

57

Step-by-step explanation:

Answer with full steps in pic

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