Question

the sum of ages of 5 children born a age of intervals of 3 years each is 50 years yungest child

Answer 1

x+x+3+x+6+x+9+x+12=50.
5x+30=50
5x=20
x=4
,so
x+12 =16

Answer 2

Answer:

Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.

According to Question now,

➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

➳ 5x + 30 = 50

➳ 5x = 50 - 30

➳ x = 20/5

➳ x = 4 years

Therefore,the age of youngest child is 4 years.