Math, asked by jhss9847, 1 year ago

The sum of ages of 5 children born at intervals of 3 years every has been 50 years. what has been age of youngest child?

Answers

Answered by danoct2004
0
The five children's ages will be :-
x, x + 3, x + 6, x + 9, x + 12.
Added together this gives:
5x + 30
Total of ages = 50

5x + 30 = 50
5x = 50 - 30
5x = 20
x = 4.
The youngest child is 4 years old
Answered by Anonymous
6

Answer:

Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.

According to Question now,

➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

➳ 5x + 30 = 50

➳ 5x = 50 - 30

➳ x = 20/5

➳ x = 4 years

Therefore,the age of youngest child is 4 years.

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