The sum of ages of 5 children born at intervals of 3 years every has been 50 years. what has been age of youngest child?
Answers
Answered by
0
The five children's ages will be :-
x, x + 3, x + 6, x + 9, x + 12.
Added together this gives:
5x + 30
Total of ages = 50
5x + 30 = 50
5x = 50 - 30
5x = 20
x = 4.
The youngest child is 4 years old
x, x + 3, x + 6, x + 9, x + 12.
Added together this gives:
5x + 30
Total of ages = 50
5x + 30 = 50
5x = 50 - 30
5x = 20
x = 4.
The youngest child is 4 years old
Answered by
6
Answer:
Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.
According to Question now,
➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
➳ 5x + 30 = 50
➳ 5x = 50 - 30
➳ x = 20/5
➳ x = 4 years
Therefore,the age of youngest child is 4 years.
Similar questions