the sum of Ages of a father and his son is 60 years if 5 years before a age of father was four times to his son then there a present ages
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let the present age of the Father and His Son be ,X and Y .
solution we know that ,
x + Y = 60
x=60-Y .......... equation (1)
again
X - 5 = 4(Y-5)
60-Y =4Y-20
60+30=4Y+Y
90 = 5Y
Y =90/5
Y = 18 Years
putting the value of Y in equation (1) we have ,
X = 60-Y
X = 60-18
X =42 years .
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