Math, asked by harjindersinghferoze, 9 months ago

The sum of ages of a man and his son at present is 100 years. Six years ago, the man was
three times as old as his son. What is the present age of the son?
(a) 20 years
colod (b) 22 years oldman
(c) 25 years
(d) 28 years
Ans please

Answers

Answered by rishin10
1

Answer:

(d)28 years

Step-by-step explanation:

Let the present age of man be x and his son be y

x+y=100

Six years ago,

age of man=x-6

age of son=y-6

Acc to the problem,

x-6=3(y-6)

x-6=3y-18

x-3y=-18+6=-12

Subtracting both we get,

4y=112

y=28 years which is the present age of the son

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