The sum of ages of a man and his
son is 45. Five yrs ago, the product
of their ages is equal to the 4times
of his father's age at that time.
The ages of father and the son
respectively are:
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Answer:
let da age of father n son b x and 45-x.
(x+5)(40-x)=4(x+5)
40x+200-x^2-5x=4x+20
31x-180-x^2=0
x^2-31x+180=0
(x-36)(x+5)=0
father's age 36years and son's age is 9years
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