the sum of ages of father and his son is 45. 5 years ago the product of their ages was 150. Find thier present age
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Let son age = x
Now let age of father = 45-x
Before 5 yrs
Age of son = x- 5
Age of father = 45-x-5= 40- x
(x-5)(40-×)=150
Now u can find value of x and hence find the agea
rifaat97:
y cant father's age be x anx sons age be Y ??
No this is a question of quadratic equation
Listen...it can be solved by any of the two ways....either by linear equation in two variables or by quadratic equation
But....in my views quadratic method is much better....as it is easy to solve
How by linear equations ? Pls tell
Linear equation u need to have two pair of equations but here u cant make 2 equations
Answered by
1
Answer:let father's age be 'x' years
according to ques sum of their ages is 45 years,
therefore son's age is 45-x years
ATQ;
(x-5) * (45-x-5) = 150
(x-5)*(40-x) = 150
40x- x^2 - 200 + 5x =150
45x - x^2 = 350
x^2-45x+350= 0
x^2 -10x - 35x + 350 = 0
x (x-10) -35 (x-10) =0
Therefore; x=10 or x=35
so present age of father is 35 years
Hope...it will help
Step-by-step explanation:
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