Question

the sum of Ages of father and his son is 60 years after 14 years father's age will be three times the age of the son find their present ages​

Answer 1

Answer:

X+Y=60 (eq 1)

X=3Y

3Y+Y=60

4Y=60

Y=15

(Put Y=15 in eq 1)

X+15 =60

X=45

Answer 2

Step-by-step explanation:

Suppose present age of father be = a

son age = 60-a

according to question after 14 years

Father age = (a+14) years

son age = (60-a+14)

= (60+14-a)

= (74-a)

$a + 14 = 3(74 - a) \\ a + 14 = 222 - 3a \\ a + 3a = 222 - 14 \\ 4a = 208 \\ a = 208 \div 4 \\ a = 52 \\ father \: present \: age \: = 52 \: years \\ \\ son \: present \: age \: = 60 - 52 \\ = 8 \: years.$

therfore ,

Father age = 52 years

son age = 8 years