Question

the sum of Ages of father and his son is 60 years after 14 years father's age will be three times the age of his son find their present ages​

Answer 1

Answer:

Step-by-step explanation:

let we take

Father=x

Son=y

So,

Sum of their ages x+y=60......(1)

After 14years ,( ,y+14) , ( x +14)

According to the question..

X+14=3(y+14)......(2)

X+14=3y+42

X-3y=28.....(3)

From (1)&(3)

Subtract x+3y =60 - x-3y =28

4y=32

Y=8

Apply the y value in eq (1)

X=52

Thus father=52

Son=8

Thanks!!!

Answer 2

Answer:

father age =52

son age = 8

Step-by-step explanation:

let father age be x

   son age be y

x+y=60

so, after 14 years

fathers age = 14+x

son age = 3(14+x)

now, we can find x and y from substitution method

the two equations are

3(14+x)=14+x(father's age in 3 times son's age)

x+y=60

now,

in 3(14+x)=14+x,

42+3y=14+x

x=28+3y

then

in x+y=60,

28+3y+y=60

28+4y=60

4y=60-28

y=32/4

y=8

now,

we have

x+y=60

x=60-8

x=52