the sum of ages of three people is 120 of the ages of second is twice the first and third is thrice the first one age. find their ages
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let the age of first one be x.....so it will be x+2x+3x=120
6x=120
x=120÷6
x=20
so,the age of first one is 20.....the age of second one's is 2x=2×20=40 and the third one's age is 3x=3×20=60
6x=120
x=120÷6
x=20
so,the age of first one is 20.....the age of second one's is 2x=2×20=40 and the third one's age is 3x=3×20=60
Answered by
6
Let the age of 1st person be x
the age of 2nd person is twice the 1st = 2x
the age of 3rd person is thrice the 1st = 3x
The sum of the three person is 120.
Therefore, x + 2x + 3x = 120
6x = 120
x = 120/6
x = 20
age of 1st person = x = 20 yrs
age of 2nd person = 2x = 2*20=40yrs
age of 3rd person = 3x = 3*20= 60yrs
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