Question

the sum of all 4 digit number containing the digits 2 4 6 8 without repetitions is​

Answer 1

Answer will be 133320.
Since During addition,
In every place we will get
"adding of 2,4,6 & 8, Six times each."
So 6(2+4+6+8)=120.
And
120
120
120
120
133320. Ans

Answer 2

The sum of all 4-digit number containing the digits 2 4 6 8 without repetitions is​ 133320.

Step-by-step explanation:

Given,

Digits = 2, 4, 6, 8

so,

Total 4-digit numbers that can be formed using 2,4,6, and 8 without repetition = 4 * 3 * 2* 1

= 24

Let the sum of unit digits of all 24 numbers be A

Let the sum of tens digits of all 24 numbers be B

Let the sum of hundreds digits of all 24 numbers be C

Let the sum of thousands digits of all 24 numbers be D

So,

(D * 10^3) + (C * 10^2) + (B * 10^1) + (A * 10^0)

As we know, each number will come at each place six times;

⇒ {6(2 + 4 + 6 + 8) * 10^3} + {6(2 + 4 + 6 + 8) * 10^2} + {6(2 + 4 + 6 + 8) * 10^1} + {6(2 + 4 + 6 + 8) * 10^0}

= 120 * 10^3 + 120 * 10^2 + 120 * 10^1 + 120 * 10^0

= 120000 + 12000 + 1200 + 120

= 133320

Learn more: 4-digit number

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