Math, asked by divyamrastogi84, 8 months ago

the sum of all areas of all sectors each of the radius 7 which is formed at sll vertecies of quadrilatera . ​

Answers

Answered by amitnrw
0

Given : sectors each of the radius 7  is formed at all vertices of quadrilateral . ​

To Find :  sum of areas of all sectors

Solution:

Let say ABCD is quadrilateral

Area of circle =  πr²   where r is radius

Area of sector = ( sector angle° / 360°)πr²

Area of sector at vertices A = ( A° / 360°)π7²

Area of sector at vertices B = ( B° / 360°)π7²

Area of sector at vertices C = ( C° / 360°)π7²

Area of sector at vertices D = ( D° / 360°)π7²

Total area

= π7²(A°  + B°  + C°  + D° ) / 360°

Sum of angles of a quadrilateral = 360°

=> A°  + B°  + C°  + D° = 360°

Hence Total area  =  π7²(360° ) / 360°

= π7²

using π = 22/7

= (22/7)7²

= 22 x 7

= 154  sq units

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Answered by XxBloodMoonXx
0

Step-by-step explanation:

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