The sum of all integers between 200 and 400 divisible by 9 is?
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The numbers lying between 200 and 400, which are divisible by 9 are,
207, 216, 225, .... 396.
First term, a = 207
Last term, l = 396
Common difference, d = 9
Let the number of terms of the A.P. be n.
an = 396 = a + (n - 1) d
396 = 207 + (n - 1) 9
9 (n - 1) = 189
n - 1 = 21
n = 22
Sum of 22 = 22 / 2 (207 + 396)
= 11(603)
Thus, the required sum is 6633.
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207, 216, 225, .... 396.
First term, a = 207
Last term, l = 396
Common difference, d = 9
Let the number of terms of the A.P. be n.
an = 396 = a + (n - 1) d
396 = 207 + (n - 1) 9
9 (n - 1) = 189
n - 1 = 21
n = 22
Sum of 22 = 22 / 2 (207 + 396)
= 11(603)
Thus, the required sum is 6633.
HOPE IT HELPS
I WANT U TO MARK IT AS BRAINLIEST ANSWER
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