the sum of all numbers in an ap is 16 and sum of their squares is 84 find the numbers
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let the terms be a-3d,a-d,a+d,a+3d so
their sum=4a=16 so a=4
now sum of their squares is 4a^2+20d^2=84
thus 64+20d^2=84 so d=1 or d=-1 so the ap is 1,3,5,7 or 7,5,3,1
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let the terms be a-3d,a-d,a+d,a+3d so
their sum=4a=16 so a=4
now sum of their squares is 4a^2+20d^2=84
thus 64+20d^2=84 so d=1 or d=-1 so the ap is 1,3,5,7 or 7,5,3,1
Hope it's helpful
Have a nice day
Keep support and follow
#vijil07
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Answer:
4 no.are a-3d,a-d,a+d,a+3d
Sum=16
4a=16
a=16/4
a=4
product=84
4a²-20d²=84
-20d²=84-64
d²=1
d=±1
the no.are 1,3,5,7 or 7,5,3,1
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